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The Stacks project

Lemma 36.5.3. Let f : X \to S be an affine morphism of schemes. For E in D_\mathit{QCoh}(\mathcal{O}_ S) we have Rf_* Lf^* E = E \otimes ^\mathbf {L}_{\mathcal{O}_ S} f_*\mathcal{O}_ X.

Proof. Since f is affine the map f_*\mathcal{O}_ X \to Rf_*\mathcal{O}_ X is an isomorphism (Cohomology of Schemes, Lemma 30.2.3). There is a canonical map E \otimes ^\mathbf {L} f_*\mathcal{O}_ X = E \otimes ^\mathbf {L} Rf_*\mathcal{O}_ X \to Rf_* Lf^* E adjoint to the map

Lf^*(E \otimes ^\mathbf {L} Rf_*\mathcal{O}_ X) = Lf^*E \otimes ^\mathbf {L} Lf^*Rf_*\mathcal{O}_ X \longrightarrow Lf^* E \otimes ^\mathbf {L} \mathcal{O}_ X = Lf^* E

coming from 1 : Lf^*E \to Lf^*E and the canonical map Lf^*Rf_*\mathcal{O}_ X \to \mathcal{O}_ X. To check the map so constructed is an isomorphism we may work locally on S. Hence we may assume S and therefore X is affine. In this case the statement is clear from the description of the derived categories D_\mathit{QCoh}(\mathcal{O}_ X) and D_\mathit{QCoh}(\mathcal{O}_ S) and the functor Lf^* given in Lemmas 36.3.5 and 36.3.8. Some details omitted. \square


Comments (2)

Comment #8577 by Haohao Liu on

Isn't it a special case of Lemma 08EU?


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