Lemma 99.3.2. In Situation 99.3.1 the functor \mathit{Hom}(\mathcal{F}, \mathcal{G}) satisfies the sheaf property for the fpqc topology.
Proof. Let \{ T_ i \to T\} _{i \in I} be an fpqc covering of schemes over B. Set X_ i = X_{T_ i} = X \times _ S T_ i and \mathcal{F}_ i = u_{T_ i} and \mathcal{G}_ i = \mathcal{G}_{T_ i}. Note that \{ X_ i \to X_ T\} _{i \in I} is an fpqc covering of X_ T, see Topologies on Spaces, Lemma 73.9.3. Thus a family of maps u_ i : \mathcal{F}_ i \to \mathcal{G}_ i such that u_ i and u_ j restrict to the same map on X_{T_ i \times _ T T_ j} comes from a unique map u : \mathcal{F}_ T \to \mathcal{G}_ T by descent (Descent on Spaces, Proposition 74.4.1). \square
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