Processing math: 100%

The Stacks project

Lemma 21.38.4. Assumptions and notation as in Situation 21.38.3. For U' \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{C}') set U = u(U') and V = p'(U') and consider the induced morphisms of ringed topoi

\xymatrix{ (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}'/U'), \mathcal{O}_{U'}) \ar[rd]_{\pi '_{U'}} \ar[rr]_{g'} & & (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}_ U) \ar[ld]^{\pi _ U} \\ & (\mathop{\mathit{Sh}}\nolimits (\mathcal{D}/V), \mathcal{O}_ V) }

Then there exists a morphism of topoi

\sigma ' : \mathop{\mathit{Sh}}\nolimits (\mathcal{D}/V) \to \mathop{\mathit{Sh}}\nolimits (\mathcal{C}'/U'),

such that setting \sigma = g' \circ \sigma ' we have \pi '_{U'} \circ \sigma ' = \text{id}, \pi _ U \circ \sigma = \text{id}, (\sigma ')^{-1} = \pi '_{U', *}, and \sigma ^{-1} = \pi _{U, *}.

Proof. Let v' : \mathcal{D}/V \to \mathcal{C}'/U' be the functor constructed in the proof of Lemma 21.38.2 starting with p' : \mathcal{C}' \to \mathcal{D}' and the object U'. Since u is a 1-morphism of fibred categories over \mathcal{D} it transforms strongly cartesian morphisms into strongly cartesian morphisms, hence the functor v = u \circ v' is the functor of the proof of Lemma 21.38.2 relative to p : \mathcal{C} \to \mathcal{D} and U. Thus our lemma follows from that lemma. \square


Comments (0)


Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.