Proof.
By Lemma 47.2.4 the inclusion R/\mathfrak p \subset \kappa (\mathfrak p) is an essential extension. Then Lemma 47.5.3 shows (2) holds. For f \in R, f \not\in \mathfrak p the map f : \kappa (\mathfrak p) \to \kappa (\mathfrak p) is an isomorphism hence the map f : E \to E is an isomorphism, see Lemma 47.5.3. Thus E is an R_\mathfrak p-module. It is injective as an R_\mathfrak p-module by Lemma 47.3.3. Finally, let E' \subset E be a nonzero injective R-submodule. Then J = (R/\mathfrak p) \cap E' is nonzero. After shrinking E' we may assume that E' is the injective hull of J (see Lemma 47.5.3 for example). Observe that R/\mathfrak p is an essential extension of J for example by Lemma 47.2.4. Hence E' \to E is an isomorphism by Lemma 47.5.3 part (3). Hence E is indecomposable.
\square
Comments (2)
Comment #3444 by Sebastian Bozlee on
Comment #3498 by Johan on
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