Lemma 61.5.7. Let A be a ring. Let V(I) \subset \mathop{\mathrm{Spec}}(A) be a closed subset which is a profinite topological space. Then there exists an ind-Zariski ring map A \to B such that \mathop{\mathrm{Spec}}(B) is w-local, the set of closed points is V(IB), and A/I \cong B/IB.
Proof. Let A \to A_ w and Z \subset Y = \mathop{\mathrm{Spec}}(A_ w) as in Lemma 61.5.3. Let T \subset Z be the inverse image of V(I). Then T \to V(I) is a homeomorphism by Topology, Lemma 5.17.8. Let B = (A_ w)_ T^\sim , see Lemma 61.5.1. It is clear that B is w-local with closed points V(IB). The ring map A/I \to B/IB is ind-Zariski and induces a homeomorphism on underlying topological spaces. Hence it is an isomorphism by Lemma 61.3.8. \square
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