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The Stacks project

Lemma 61.5.8. Let A be a ring such that X = \mathop{\mathrm{Spec}}(A) is w-local. Let I \subset A be the radical ideal cutting out the set X_0 of closed points in X. Let A \to B be a ring map inducing algebraic extensions on residue fields at primes. Then

  1. every point of Z = V(IB) is a closed point of \mathop{\mathrm{Spec}}(B),

  2. there exists an ind-Zariski ring map B \to C such that

    1. B/IB \to C/IC is an isomorphism,

    2. the space Y = \mathop{\mathrm{Spec}}(C) is w-local,

    3. the induced map p : Y \to X is w-local, and

    4. p^{-1}(X_0) is the set of closed points of Y.

Proof. By Lemma 61.5.6 applied to A/I \to B/IB all points of Z = V(IB) = \mathop{\mathrm{Spec}}(B/IB) are closed, in fact \mathop{\mathrm{Spec}}(B/IB) is a profinite space. To finish the proof we apply Lemma 61.5.7 to IB \subset B. \square


Comments (2)

Comment #2532 by Brian Conrad on

In (2) you should say can also be taken to be flat (used in paragraph 2 of the proof of 52.6.7 in 097B).

Comment #2533 by Brian Conrad on

Oops, disregard the preceding comment (since ind-Zariski maps are always flat); it's been a long day...

There are also:

  • 2 comment(s) on Section 61.5: Constructing w-local affine schemes

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