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The Stacks project

Lemma 33.38.10. Let X be a Noetherian reduced separated scheme of dimension 1. Then X has an ample invertible sheaf.

Proof. Let Z_ i, i = 1, \ldots , n be the irreducible components of X. We view these as reduced closed subschemes of X. By Lemma 33.38.6 there exist ample invertible sheaves \mathcal{L}_ i on Z_ i. Set T = \bigcup _{i \not= j} Z_ i \cap Z_ j. As X is Noetherian of dimension 1, the set T is finite and consists of closed points of X. For each i we may, possibly after replacing \mathcal{L}_ i by a power, choose s_ i \in \Gamma (Z_ i, \mathcal{L}_ i) such that (Z_ i)_{s_ i} is affine and contains T \cap Z_ i, see Properties, Lemma 28.29.6.

By Lemma 33.38.8 we can find an invertible sheaf \mathcal{L} on X and s \in \Gamma (X, \mathcal{L}) such that (\mathcal{L}, s)|_{Z_ i} = (\mathcal{L}_ i, s_ i). Observe that X_ s contains T and is set theoretically equal to the affine closed subschemes (Z_ i)_{s_ i}. Thus it is affine by Limits, Lemma 32.11.3. To finish the proof, it suffices to find for every x \in X, x \not\in T an integer m > 0 and a section t \in \Gamma (X, \mathcal{L}^{\otimes m}) such that X_ t is affine and x \in X_ t. Since x \not\in T we see that x \in Z_ i for some unique i, say i = 1. Let Z \subset X be the reduced closed subscheme whose underlying topological space is Z_2 \cup \ldots \cup Z_ n. Let \mathcal{I} \subset \mathcal{O}_ X be the ideal sheaf of Z. Denote that \mathcal{I}_1 \subset \mathcal{O}_{Z_1} the inverse image of this ideal sheaf under the inclusion morphism Z_1 \to X. Observe that

\Gamma (X, \mathcal{I}\mathcal{L}^{\otimes m}) = \Gamma (Z_1, \mathcal{I}_1 \mathcal{L}_1^{\otimes m})

see Remark 33.38.9. Thus it suffices to find m > 0 and t \in \Gamma (Z_1, \mathcal{I}_1 \mathcal{L}_1^{\otimes m}) with x \in (Z_1)_ t affine. Since \mathcal{L}_1 is ample and since x is not in Z_1 \cap T = V(\mathcal{I}_1) we can find a section t_1 \in \Gamma (Z_1, \mathcal{I}_1 \mathcal{L}_1^{\otimes m_1}) with x \in (Z_1)_{t_1}, see Properties, Proposition 28.26.13. Since \mathcal{L}_1 is ample we can find a section t_2 \in \Gamma (Z_1, \mathcal{L}_1^{\otimes m_2}) with x \in (Z_1)_{t_2} and (Z_1)_{t_2} affine, see Properties, Definition 28.26.1. Set m = m_1 + m_2 and t = t_1 t_2. Then t \in \Gamma (Z_1, \mathcal{I}_1 \mathcal{L}_1^{\otimes m}) with x \in (Z_1)_ t by construction and (Z_1)_ t is affine by Properties, Lemma 28.26.4. \square


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