Lemma 33.43.11. Let X be a separated scheme of finite type over k. If \dim (X) \leq 1 and no irreducible component of X is proper of dimension 1, then X is affine.
Proof. Let X = \bigcup X_ i be the decomposition of X into irreducible components. We think of X_ i as an integral scheme (using the reduced induced scheme structure, see Schemes, Definition 26.12.5). In particular X_ i is a singleton (hence affine) or a curve hence affine by Lemma 33.43.10. Then \coprod X_ i \to X is finite surjective and \coprod X_ i is affine. Thus we see that X is affine by Cohomology of Schemes, Lemma 30.13.3. \square
Comments (0)
There are also: