Lemma 68.17.7. Let $S$ be a scheme. Let $f : X \to Y$, $g : Z \to Y$ be morphisms of algebraic spaces over $S$. If $X$ and $Z$ are decent (resp. reasonable, resp. have property $(\beta )$ of Lemma 68.5.1), then so does $X \times _ Y Z$.
Proof. Namely, by Lemma 68.17.3 the morphism $X \to Y$ has the property. Then the base change $X \times _ Y Z \to Z$ has the property by Lemma 68.17.4. And finally this implies $X \times _ Y Z$ has the property by Lemma 68.17.5. $\square$
Post a comment
Your email address will not be published. Required fields are marked.
In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$
). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).
All contributions are licensed under the GNU Free Documentation License.
Comments (0)