Lemma 68.18.6. Let S be a scheme. Let f : X \to Y be a morphism of algebraic spaces over S. Let y \in |Y| and assume that y is represented by a quasi-compact monomorphism \mathop{\mathrm{Spec}}(k) \to Y. Then |X_ k| \to |X| is a homeomorphism onto f^{-1}(\{ y\} ) \subset |X| with induced topology.
Fibers of field points of algebraic spaces have the expected Zariski topologies.
Proof. We will use Properties of Spaces, Lemma 66.16.7 and Morphisms of Spaces, Lemma 67.10.9 without further mention. Let V \to Y be an étale morphism with V affine such that there exists a v \in V mapping to y. Since \mathop{\mathrm{Spec}}(k) \to Y is quasi-compact there are a finite number of points of V mapping to y (Lemma 68.4.5). After shrinking V we may assume v is the only one. Choose a scheme U and a surjective étale morphism U \to X. Consider the commutative diagram
Since U_ v \to U_ V identifies U_ v with a subset of U_ V with the induced topology (Schemes, Lemma 26.18.5), and since |U_ V| \to |X_ V| and |U_ v| \to |X_ v| are surjective and open, we see that |X_ v| \to |X_ V| is a homeomorphism onto its image (with induced topology). On the other hand, the inverse image of f^{-1}(\{ y\} ) under the open map |X_ V| \to |X| is equal to |X_ v|. We conclude that |X_ v| \to f^{-1}(\{ y\} ) is open. The morphism X_ v \to X factors through X_ k and |X_ k| \to |X| is injective with image f^{-1}(\{ y\} ) by Properties of Spaces, Lemma 66.4.3. Using |X_ v| \to |X_ k| \to f^{-1}(\{ y\} ) the lemma follows because X_ v \to X_ k is surjective. \square
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