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The Stacks project

Fibers of field points of algebraic spaces have the expected Zariski topologies.

Lemma 68.18.6. Let S be a scheme. Let f : X \to Y be a morphism of algebraic spaces over S. Let y \in |Y| and assume that y is represented by a quasi-compact monomorphism \mathop{\mathrm{Spec}}(k) \to Y. Then |X_ k| \to |X| is a homeomorphism onto f^{-1}(\{ y\} ) \subset |X| with induced topology.

Proof. We will use Properties of Spaces, Lemma 66.16.7 and Morphisms of Spaces, Lemma 67.10.9 without further mention. Let V \to Y be an étale morphism with V affine such that there exists a v \in V mapping to y. Since \mathop{\mathrm{Spec}}(k) \to Y is quasi-compact there are a finite number of points of V mapping to y (Lemma 68.4.5). After shrinking V we may assume v is the only one. Choose a scheme U and a surjective étale morphism U \to X. Consider the commutative diagram

\xymatrix{ U \ar[d] & U_ V \ar[l] \ar[d] & U_ v \ar[l] \ar[d] \\ X \ar[d] & X_ V \ar[l] \ar[d] & X_ v \ar[l] \ar[d] \\ Y & V \ar[l] & v \ar[l] }

Since U_ v \to U_ V identifies U_ v with a subset of U_ V with the induced topology (Schemes, Lemma 26.18.5), and since |U_ V| \to |X_ V| and |U_ v| \to |X_ v| are surjective and open, we see that |X_ v| \to |X_ V| is a homeomorphism onto its image (with induced topology). On the other hand, the inverse image of f^{-1}(\{ y\} ) under the open map |X_ V| \to |X| is equal to |X_ v|. We conclude that |X_ v| \to f^{-1}(\{ y\} ) is open. The morphism X_ v \to X factors through X_ k and |X_ k| \to |X| is injective with image f^{-1}(\{ y\} ) by Properties of Spaces, Lemma 66.4.3. Using |X_ v| \to |X_ k| \to f^{-1}(\{ y\} ) the lemma follows because X_ v \to X_ k is surjective. \square


Comments (4)

Comment #1110 by Evan Warner on

Suggested slogan: Fibers of field points of algebraic spaces have the expected Zariski topologies.

Comment #1111 by Evan Warner on

minor typo: presumably we want a morphism over S.

Comment #1112 by Evan Warner on

minor typo: presumably we want a morphism over S.


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