Lemma 58.19.2. In Situation 58.19.1. Assume one of the following holds
\dim (A/\mathfrak p) \geq 2 for every minimal prime \mathfrak p \subset A with f \not\in \mathfrak p, or
every connected component of U meets U_0.
Then
is a faithful functor.
Lemma 58.19.2. In Situation 58.19.1. Assume one of the following holds
\dim (A/\mathfrak p) \geq 2 for every minimal prime \mathfrak p \subset A with f \not\in \mathfrak p, or
every connected component of U meets U_0.
Then
is a faithful functor.
Proof. Case (2) is immediate from Lemma 58.17.5. Assumption (1) implies every irreducible component of U meets U_0, see Algebra, Lemma 10.60.13. Hence (1) follows from (2). \square
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