Lemma 49.4.3. Let A \to B be a finite flat map of Noetherian rings. Then \text{Trace}_{B/A} \in \omega _{B/A} is the trace element.
Proof. Suppose we have A \to A_1 with A_1 Noetherian and a product decomposition B \otimes _ A A_1 = C \times D with A_1 \to C finite. Of course in this case A_1 \to D is also finite. Set B_1 = B \otimes _ A A_1. Since the construction of traces commutes with base change we see that \text{Trace}_{B/A} maps to \text{Trace}_{B_1/A_1}. Thus the proof is finished by noticing that \text{Trace}_{B_1/A_1} = (\text{Trace}_{C/A_1}, \text{Trace}_{D/A_1}) under the isomorphism \omega _{B_1/A_1} = \omega _{C/A_1} \times \omega _{D/A_1} of Lemma 49.2.7. \square
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