Lemma 58.14.2. Let $k$ be a field with perfection $k^{perf}$. Let $X$ be a connected scheme over $k$. Then $X_{k^{perf}}$ is connected and $\pi _1(X_{k^{perf}}) \to \pi _1(X)$ is an isomorphism.
Proof. Special case of topological invariance of the fundamental group. See Proposition 58.8.4. To see that $\mathop{\mathrm{Spec}}(k^{perf}) \to \mathop{\mathrm{Spec}}(k)$ is a universal homeomorphism you can use Algebra, Lemma 10.46.10. $\square$
Post a comment
Your email address will not be published. Required fields are marked.
In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$
). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).
All contributions are licensed under the GNU Free Documentation License.
Comments (0)