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The Stacks project

Remark 29.49.13. Here is a generalization of the category of irreducible schemes and dominant rational maps. For a scheme X denote X^0 the set of points x \in X with \dim (\mathcal{O}_{X, x}) = 0, in other words, X^0 is the set of generic points of irreducible components of X. Then we can consider the category with

  1. objects are schemes X such that every quasi-compact open has finitely many irreducible components, and

  2. morphisms from X to Y are rational maps f : U \to Y from X to Y such that f(U^0) = Y^0.

If U \subset X is a dense open of a scheme, then U^0 \subset X^0 need not be an equality, but if X is an object of our category, then this is the case. Thus given two morphisms in our category, the composition is well defined and a morphism in our category.


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