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The Stacks project

Lemma 48.25.6. Let f : X \to Y and g : Y \to Z be morphisms. Assume that the fibres X_ y, Y_ z and X_ z of f, g, and g \circ f are locally Noetherian.

  1. If f is Gorenstein at x and g is Gorenstein at f(x), then g \circ f is Gorenstein at x.

  2. If f and g are Gorenstein, then g \circ f is Gorenstein.

  3. If g \circ f is Gorenstein at x and f is flat at x, then f is Gorenstein at x and g is Gorenstein at f(x).

  4. If g \circ f is Gorenstein and f is flat, then f is Gorenstein and g is Gorenstein at every point in the image of f.

Proof. After translating into algebra this follows from Dualizing Complexes, Lemma 47.21.8. \square


Comments (2)

Comment #7718 by Andrew on

There's a typo in (4) with .


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