Lemma 99.11.5. In Situation 99.11.1 let \sigma : B \to X be a section. Then \mathcal{P}\! \mathit{ic}_{X/B, \sigma } as defined above is a stack in groupoids over (\mathit{Sch}/S)_{fppf}.
Proof. We already know that \mathcal{P}\! \mathit{ic}_{X/B} is a stack in groupoids over (\mathit{Sch}/S)_{fppf} by Examples of Stacks, Lemma 95.16.1. Let us show descent for objects for \mathcal{P}\! \mathit{ic}_{X/B, \sigma }. Let \{ T_ i \to T\} be an fppf covering and let \xi _ i = (T_ i, h_ i, \mathcal{L}_ i, \alpha _ i) be an object of \mathcal{P}\! \mathit{ic}_{X/B, \sigma } lying over T_ i, and let \varphi _{ij} : \text{pr}_0^*\xi _ i \to \text{pr}_1^*\xi _ j be a descent datum. Applying the result for \mathcal{P}\! \mathit{ic}_{X/B} we see that we may assume we have an object (T, h, \mathcal{L}) of \mathcal{P}\! \mathit{ic}_{X/B} over T which pulls back to \xi _ i for all i. Then we get
Since the maps \varphi _{ij} are compatible with the \alpha _ i we see that \alpha _ i and \alpha _ j pullback to the same map on T_ i \times _ T T_ j. By descent of quasi-coherent sheaves (Descent, Proposition 35.5.2, we see that the \alpha _ i are the restriction of a single map \alpha : \mathcal{O}_ T \to \sigma _ T^*\mathcal{L} as desired. We omit the proof of descent for morphisms. \square
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