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The Stacks project

Lemma 71.14.6. Let S be a scheme. Let f : X \to Y be a morphism of algebraic spaces over S. Let \mathcal{L} be an invertible \mathcal{O}_ X-module. The following are equivalent

  1. \mathcal{L} is ample on X/Y,

  2. for every scheme Z and every morphism Z \to Y the algebraic space X_ Z = Z \times _ Y X is a scheme and the pullback \mathcal{L}_ Z is ample on X_ Z/Z,

  3. for every affine scheme Z and every morphism Z \to Y the algebraic space X_ Z = Z \times _ Y X is a scheme and the pullback \mathcal{L}_ Z is ample on X_ Z/Z,

  4. there exists a scheme V and a surjective étale morphism V \to Y such that the algebraic space X_ V = V \times _ Y X is a scheme and the pullback \mathcal{L}_ V is ample on X_ V/V.

Proof. Parts (1) and (2) are equivalent by definition. The implication (2) \Rightarrow (3) is immediate. If (3) holds and Z \to Y is as in (2), then we see that X_ Z \to Z is affine locally on Z representable. Hence X_ Z is a scheme for example by Properties of Spaces, Lemma 66.13.1. Then it follows that \mathcal{L}_ Z is ample on X_ Z/Z because it holds locally on Z and we can use Morphisms, Lemma 29.37.4. Thus (1), (2), and (3) are equivalent. Clearly these conditions imply (4).

Assume (4). Let Z \to Y be a morphism with Z affine. Then U = V \times _ Y Z \to Z is a surjective étale morphism such that the pullback of \mathcal{L}_ Z by X_ U \to X_ Z is relatively ample on X_ U/U. Of course we may replace U by an affine open. It follows that \mathcal{L}_ Z is ample on X_ Z/Z by Lemma 71.14.5. Thus (4) \Rightarrow (3) and the proof is complete. \square


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