Lemma 76.31.2. Let S be a scheme. Let f : X \to Y be a finite type morphism of algebraic spaces over S. Let
n_{X/Y} : |Y| \to \{ -\infty , 0, 1, 2, 3, \ldots \}
be the function which associates to y \in |Y| the integer discussed in Lemma 76.31.1. If g : Y' \to Y is a morphism then
n_{X'/Y'} = n_{X/Y} \circ |g|
where X' \to Y' is the base change of f.
Comments (2)
Comment #8141 by Laurent Moret-Bailly on
Comment #8233 by Stacks Project on