Lemma 84.5.1. Let S be a scheme. Let X be an algebraic space over S. Let \mathcal{F} be a sheaf on X_{\acute{e}tale}. Then \pi _ X^{-1}\mathcal{F} is given by the rule
(\pi _ X^{-1}\mathcal{F})(Y) = \Gamma (Y_{\acute{e}tale}, f_{small}^{-1}\mathcal{F})
for f : Y \to X in (\textit{Spaces}/X)_{\acute{e}tale}. Moreover, \pi _ Y^{-1}\mathcal{F} satisfies the sheaf condition with respect to smooth, syntomic, fppf, fpqc, and ph coverings.
Proof.
Since pullback is transitive and f_{small} = \pi _ X \circ i_ f (see above) we see that i_ f^{-1} \pi _ X^{-1}\mathcal{F} = f_{small}^{-1}\mathcal{F}. This shows that \pi _ X^{-1} has the description given in the lemma.
To prove that \pi _ X^{-1}\mathcal{F} is a sheaf for the ph topology it suffices by Topologies on Spaces, Lemma 73.8.7 to show that for a surjective proper morphism V \to U of algebraic spaces over X we have (\pi _ X^{-1}\mathcal{F})(U) is the equalizer of the two maps (\pi _ X^{-1}\mathcal{F})(V) \to (\pi _ X^{-1}\mathcal{F})(V \times _ U V). This we have seen in Lemma 84.4.1.
The case of smooth, syntomic, fppf coverings follows from the case of ph coverings by Topologies on Spaces, Lemma 73.8.2.
Let \mathcal{U} = \{ U_ i \to U\} _{i \in I} be an fpqc covering of algebraic spaces over X. Let s_ i \in (\pi _ X^{-1}\mathcal{F})(U_ i) be sections which agree over U_ i \times _ U U_ j. We have to prove there exists a unique s \in (\pi _ X^{-1}\mathcal{F})(U) restricting to s_ i over U_ i. Case I: U and U_ i are schemes. This case follows from Étale Cohomology, Lemma 59.39.2. Case II: U is a scheme. Here we choose surjective étale morphisms T_ i \to U_ i where T_ i is a scheme. Then \mathcal{T} = \{ T_ i \to U\} is an fpqc covering by schemes and by case I the result holds for \mathcal{T}. We omit the verification that this implies the result for \mathcal{U}. Case III: general case. Let W \to U be a surjective étale morphism, where W is a scheme. Then \mathcal{W} = \{ U_ i \times _ U W \to W\} is an fpqc covering (by algebraic spaces) of the scheme W. By case II the result hold for \mathcal{W}. We omit the verification that this implies the result for \mathcal{U}.
\square
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