Lemma 108.7.4. Let B be an algebraic space. Let \pi : X \to Y be an open immersion of algebraic spaces which are separated and of finite presentation over B. Then \pi induces an open immersion \mathrm{Hilb}_{X/B} \to \mathrm{Hilb}_{Y/B}.
Proof. Omitted. Hint: If Z \subset X_ T is a closed subscheme which is proper over T, then Z is also closed in Y_ T. Thus we obtain the transformation \mathrm{Hilb}_{X/B} \to \mathrm{Hilb}_{Y/B}. If Z \subset Y_ T is an element of \mathrm{Hilb}_{Y/B}(T) and for t \in T we have |Z_ t| \subset |X_ t|, then the same is true for t' \in T in a neighbourhood of t. \square
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