Lemma 108.7.1. The diagonal of \mathrm{Hilb}_{X/B} \to B is a closed immersion of finite presentation.
108.7 Properties of the Hilbert functor
Let f : X \to B be a morphism of algebraic spaces which is separated and of finite presentation. Then \mathrm{Hilb}_{X/B} is an algebraic space locally of finite presentation over B. See Quot, Proposition 99.9.4.
Proof. In Quot, Lemma 99.9.2 we have seen that \mathrm{Hilb}_{X/B} = \mathrm{Quot}_{\mathcal{O}_ X/X/B}. Hence this follows from Lemma 108.5.1. \square
Lemma 108.7.2. The morphism \mathrm{Hilb}_{X/B} \to B is separated and locally of finite presentation.
Proof. To check \mathrm{Hilb}_{X/B} \to B is separated we have to show that its diagonal is a closed immersion. This is true by Lemma 108.7.1. The second statement is part of Quot, Proposition 99.9.4. \square
Lemma 108.7.3. Assume X \to B is proper as well as of finite presentation. Then \mathrm{Hilb}_{X/B} \to B satisfies the existence part of the valuative criterion (Morphisms of Spaces, Definition 67.41.1).
Proof. In Quot, Lemma 99.9.2 we have seen that \mathrm{Hilb}_{X/B} = \mathrm{Quot}_{\mathcal{O}_ X/X/B}. Hence this follows from Lemma 108.5.3. \square
Lemma 108.7.4. Let B be an algebraic space. Let \pi : X \to Y be an open immersion of algebraic spaces which are separated and of finite presentation over B. Then \pi induces an open immersion \mathrm{Hilb}_{X/B} \to \mathrm{Hilb}_{Y/B}.
Proof. Omitted. Hint: If Z \subset X_ T is a closed subscheme which is proper over T, then Z is also closed in Y_ T. Thus we obtain the transformation \mathrm{Hilb}_{X/B} \to \mathrm{Hilb}_{Y/B}. If Z \subset Y_ T is an element of \mathrm{Hilb}_{Y/B}(T) and for t \in T we have |Z_ t| \subset |X_ t|, then the same is true for t' \in T in a neighbourhood of t. \square
Lemma 108.7.5. Let B be an algebraic space. Let \pi : X \to Y be a closed immersion of algebraic spaces which are separated and of finite presentation over B. Then \pi induces a closed immersion \mathrm{Hilb}_{X/B} \to \mathrm{Hilb}_{Y/B}.
Proof. Since \pi is a closed immersion, it is immediate that given a closed subscheme Z \subset X_ T, we can view Z as a closed subscheme of X_ T. Thus we obtain the transformation \mathrm{Hilb}_{X/B} \to \mathrm{Hilb}_{Y/B}. This transformation is immediately seen to be a monomorphism. To prove that it is a closed immersion, you can use Lemma 108.5.8 for the map \mathcal{O}_ Y \to \mathcal{O}_ X and the identifications \mathrm{Hilb}_{X/B} = \mathrm{Quot}_{\mathcal{O}_ X/X/B}, \mathrm{Hilb}_{Y/B} = \mathrm{Quot}_{\mathcal{O}_ Y/Y/B} of Quot, Lemma 99.9.2. \square
Remark 108.7.6 (Numerical invariants). Let f : X \to B be as in the introduction to this section. Let I be a set and for i \in I let E_ i \in D(\mathcal{O}_ X) be perfect. Let P : I \to \mathbf{Z} be a function. Recall that \mathrm{Hilb}_{X/B} = \mathrm{Quot}_{\mathcal{O}_ X/X/B}, see Quot, Lemma 99.9.2. Thus we can define
where \mathrm{Quot}^ P_{\mathcal{O}_ X/X/B} is as in Remark 108.5.9. The morphism
is a flat closed immersion which is an open and closed immersion for example if I is finite, or B is locally Noetherian, or I = \mathbf{Z} and E_ i = \mathcal{L}^{\otimes i} for some invertible \mathcal{O}_ X-module \mathcal{L}. In the last case we sometimes use the notation \mathrm{Hilb}^{P, \mathcal{L}}_{X/B}.
Lemma 108.7.7. Let f : X \to B be a proper morphism of finite presentation of algebraic spaces. Let \mathcal{L} be an invertible \mathcal{O}_ X-module ample on X/B, see Divisors on Spaces, Definition 71.14.1. The algebraic space \mathrm{Hilb}^ P_{X/B} parametrizing closed subschemes having Hilbert polynomial P with respect to \mathcal{L} is proper over B.
Proof. Recall that \mathrm{Hilb}_{X/B} = \mathrm{Quot}_{\mathcal{O}_ X/X/B}, see Quot, Lemma 99.9.2. Thus this lemma is an immediate consequence of Lemma 108.6.3. \square
Lemma 108.7.8. Let f : X \to B be a separated morphism of finite presentation of algebraic spaces. Let \mathcal{L} be an invertible \mathcal{O}_ X-module ample on X/B, see Divisors on Spaces, Definition 71.14.1. The algebraic space \mathrm{Hilb}^ P_{X/B} parametrizing closed subschemes having Hilbert polynomial P with respect to \mathcal{L} is separated of finite presentation over B.
Proof. Recall that \mathrm{Hilb}_{X/B} = \mathrm{Quot}_{\mathcal{O}_ X/X/B}, see Quot, Lemma 99.9.2. Thus this lemma is an immediate consequence of Lemma 108.6.4. \square
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