Lemma 106.14.1. Let p : \mathcal{X} \to Y be a morphism of an algebraic stack to an algebraic space. Assume
\mathcal{I}_\mathcal {X} \to \mathcal{X} is finite,
Y is locally Noetherian, and
p is locally of finite type.
Let f : \mathcal{X} \to M be the moduli space constructed in Theorem 106.13.9. Then M \to Y is locally of finite type.
Proof.
Since f is a uniform categorical moduli space we obtain the morphism M \to Y. It suffices to check that M \to Y is locally of finite type étale locally on M and Y. Since f is a uniform categorical moduli space, we may first replace Y by an affine scheme étale over Y. Next, we may choose I and g_ i : \mathcal{X}_ i \to \mathcal{X} as in Lemma 106.13.8. Then by Lemma 106.13.10 we reduce to the case \mathcal{X} = \mathcal{X}_ i. In other words, we may assume \mathcal{X} is well-nigh affine. In this case we have Y = \mathop{\mathrm{Spec}}(A_0), we have \mathcal{X} = [U/R] with U = \mathop{\mathrm{Spec}}(A) and M = \mathop{\mathrm{Spec}}(C) where C \subset A is the set of R-invariant functions on U. See Lemmas 106.13.2 and 106.13.4. Then A_0 is Noetherian and A_0 \to A is of finite type. Moreover A is integral over C by Groupoids, Lemma 39.23.4, hence finite over C (being of finite type over A_0). Thus we may finally apply Algebra, Lemma 10.51.7 to conclude.
\square
Comments (2)
Comment #6704 by Raymond on
Comment #6907 by Johan on