Theorem 106.13.9 (Keel-Mori). Let \mathcal{X} be an algebraic stack. Assume \mathcal{I}_\mathcal {X} \to \mathcal{X} is finite. Then there exists a uniform categorical moduli space
and f is separated, quasi-compact, and a universal homeomorphism.
Theorem 106.13.9 (Keel-Mori). Let \mathcal{X} be an algebraic stack. Assume \mathcal{I}_\mathcal {X} \to \mathcal{X} is finite. Then there exists a uniform categorical moduli space
and f is separated, quasi-compact, and a universal homeomorphism.
Proof. We choose a set I1 and for i \in I a morphism of algebraic stacks g_ i : \mathcal{X}_ i \to \mathcal{X} as in Lemma 106.13.8; we will use all of the properties listed in this lemma without further mention. Let
be as in Lemma 106.13.4. Consider the stacks
for i, j \in I. The projections \mathcal{X}_{ij} \to \mathcal{X}_ i and \mathcal{X}_{ij} \to \mathcal{X}_ j are separated by Morphisms of Stacks, Lemma 101.4.4, étale by Morphisms of Stacks, Lemma 101.35.3, and induce isomorphisms on automorphism groups (as in Morphisms of Stacks, Remark 101.19.5) by Morphisms of Stacks, Lemma 101.45.5. Thus we may apply Lemma 106.13.7 to find a commutative diagram
with cartesian squares where M_{ij} \to M_ i and M_{ij} \to M_ j are separated étale morphisms of schemes; here we also use that f_ i is a uniform categorical quotient by Lemma 106.13.6. Claim:
is an étale equivalence relation.
Proof of the claim. Set R = \coprod M_{ij} and U = \coprod M_ i. We have already seen that t : R \to U and s : R \to U are étale. Let us construct a morphism c : R \times _{s, U, t} R \to R compatible with \text{pr}_{13} : U \times U \times U \to U \times U. Namely, for i, j, k \in I we consider
Arguing exactly as in the previous paragraph, we find that M_{ijk} = M_{ij} \times _{M_ j} M_{jk} is a categorical moduli space for \mathcal{X}_{ijk}. In particular, there is a canonical morphism M_{ijk} = M_{ij} \times _{M_ j} M_{jk} \to M_{ik} coming from the projection \mathcal{X}_{ijk} \to \mathcal{X}_{ik}. Putting these morphisms together we obtain the morphism c. In a similar fashion we construct a morphism e : U \to R compatible with \Delta : U \to U \times U and i : R \to R compatible with the flip U \times U \to U \times U. Let k be an algebraically closed field. Then
is bijective on isomorphism classes and the same remains true after any base change by a morphism M' \to M. This follows from our choice of f_ i and Morphisms of Stacks, Lemmas 101.14.5 and 101.14.6. By construction of 2-fibred products the diagram
is a fibre product of categories. By our choice of g_ i the functors in this diagram induce bijections on automorphism groups. It follows that this diagram induces a fibre product diagram on sets of isomorphism classes! Thus we see that
where |\mathop{\mathrm{Mor}}\nolimits (\mathop{\mathrm{Spec}}(k), \mathcal{X})| denotes the set of isomorphism classes. In particular, for any algebraically closed field k the map on k-valued point is an equivalence relation. We conclude the claim holds by Groupoids, Lemma 39.3.5.
Let M = U/R be the algebraic space which is the quotient of the above étale equivalence relation, see Spaces, Theorem 65.10.5. There is a canonical morphism f : \mathcal{X} \to M fitting into commutative diagrams
Namely, such a morphism f is given by a functor
for any scheme T compatible with base change. Let a : T \to \mathcal{X} be an object of the left hand side. We obtain an étale covering \{ T_ i \to T\} with T_ i = \mathcal{X}_ i \times _\mathcal {X} T and morphisms a_ i : T_ i \to \mathcal{X}_ i. Then we get b_ i = f_ i \circ a_ i : T_ i \to M_ i. Since T_ i \times _ T T_ j = \mathcal{X}_{ij} \times _\mathcal {X} T we moreover get a morphism a_{ij} : T_ i \times _ T T_ j \to \mathcal{X}_{ij}. Setting b_{ij} = f_{ij} \circ a_{ij} we find that b_ i \times b_ j factors through the monomorphism M_{ij} \to M_ i \times M_ j. Hence the morphisms
agree on T_ i \times _ T T_ j. As M is a sheaf for the étale topology, we see that these morphisms glue to a unique morphism b = f(a) : T \to M. We omit the verification that this construction is compatible with base change and we omit the verification that the diagrams (106.13.9.1) commute.
Claim: the diagrams (106.13.9.1) are cartesian. To see this we study the induced morphism
This is a morphism of stacks étale over \mathcal{X} and hence h_ i is étale (Morphisms of Stacks, Lemma 101.35.6). Since g_ i is separated, we see h_ i is separated (use Morphisms of Stacks, Lemma 101.4.12 and the fact seen above that the diagonal of \mathcal{X} is separated). The morphism h_ i induces isomorphisms on automorphism groups (Morphisms of Stacks, Remark 101.19.5) as this is true for g_ i. For an algebraically closed field k the diagram
is a catesian diagram of categories and the top arrow induces bijections on automorphism groups. On the other hand, we have
by what we said above. Thus the right vertical arrow in the cartesian diagram above is a bijection on isomorphism classes. We conclude that |\mathop{\mathrm{Mor}}\nolimits (\mathop{\mathrm{Spec}}(k), M_ i \times _ M \mathcal{X})| \to M_ i(k) is bijective. Review: h_ i is a separated, étale, induces isomorphisms on automorphism groups (as in Morphisms of Stacks, Remark 101.19.5), and induces an equivalence on fibre categories over algebraically closed fields. Hence it is an isomorphism by Morphisms of Stacks, Lemma 101.45.7.
From the claim we get in particular the following: we have a surjective étale morphism U \to M such that the base change of f is separated, quasi-compact, and a universal homeomorphism. It follows that f is separated, quasi-compact, and a universal homeomorphism. See Morphisms of Stacks, Lemma 101.4.5, 101.7.10, and 101.15.5
To finish the proof we have to show that f : \mathcal{X} \to M is a uniform categorical moduli space. To prove this it suffices to show that given a flat morphism M' \to M of algebraic spaces, the base change
is a categorical moduli space. Thus we consider a morphism
where E is an algebraic space. For each i we know that f_ i is a uniform categorical moduli space. Hence we obtain
Since \{ M' \times _ M M_ i \to M'\} is an étale covering, to obtain the desired morphism \psi : M' \to E it suffices to show that \psi _ i and \psi _ j agree over M' \times _ M M_ i \times _ M M_ j = M' \times _ M M_{ij}. This follows easily from the fact that f_{ij} : \mathcal{X}_{ij} = \mathcal{X}_ i \times _\mathcal {X} \mathcal{X}_ j \to M_{ij} is a uniform categorical quotient; details omitted. Then finally one shows that \psi fits into the commutative diagram
because “\{ M' \times _ M \mathcal{X}_ i \to M' \times _ M \mathcal{X}\} is an étale covering” and the morphisms \psi _ i fit into the corresponding commutative diagrams by construction. This finishes the proof of the Keel-Mori theorem. \square
Comments (0)