Lemma 93.9.10. In Situation 93.9.9 there is an equivalence
Proof. It suffices to show that the functors of Lemma 93.9.6 define an equivalence
because then we can apply Lemma 93.9.7 to translate into rings. To do this we construct a quasi-inverse. Denote $F_ i : \mathcal{D}\! \mathit{ef}_{U_ i} \to \mathcal{D}\! \mathit{ef}_{U_{12}}$ the functor of Lemma 93.9.6. An object of the RHS is given by an $A$ in $\mathcal{C}_\Lambda $, objects $(A, V_1) \to (k, U_1)$ and $(A, V_2) \to (k, U_2)$, and a morphism
Now $F_ i(A, V_ i) = (A, V_{i, 3 - i})$ where $V_{i, 3 - i} \subset V_ i$ is the open subscheme whose base change to $k$ is $U_{12} \subset U_ i$. The morphism $g$ defines an isomorphism $V_{1, 2} \to V_{2, 1}$ of schemes over $A$ compatible with $\text{id} : U_{12} \to U_{12}$ over $k$. Thus $(\{ 1, 2\} , V_ i, V_{i, 3 - i}, g, g^{-1})$ is a glueing data as in Schemes, Section 26.14. Let $Y$ be the glueing, see Schemes, Lemma 26.14.1. Then $Y$ is a scheme over $A$ and the compatibilities mentioned above show that there is a canonical isomorphism $Y \times _{\mathop{\mathrm{Spec}}(A)} \mathop{\mathrm{Spec}}(k) = X$. Thus $(A, Y) \to (k, X)$ is an object of $\mathcal{D}\! \mathit{ef}_ X$. We omit the verification that this construction is a functor and is quasi-inverse to the given one. $\square$
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