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The Stacks project

Lemma 76.29.1. Let S be a scheme. Let f : X \to Y be a morphism of algebraic spaces over S. Let y \in |Y|. The following are equivalent

  1. for some morphism \mathop{\mathrm{Spec}}(k) \to Y in the equivalence class of y the algebraic space X_ k is geometrically reduced over k,

  2. for every morphism \mathop{\mathrm{Spec}}(k) \to Y in the equivalence class of y the algebraic space X_ k is geometrically reduced over k,

  3. for every morphism \mathop{\mathrm{Spec}}(k) \to Y in the equivalence class of y the algebraic space X_ k is reduced.

Proof. This follows immediately from Spaces over Fields, Lemma 72.11.6 and the definition of the equivalence relation defining |X| given in Properties of Spaces, Section 66.4. \square


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