Lemma 47.25.7. Let R \to A be a finite type homomorphism of Noetherian rings. Let \mathfrak q \subset A be a prime ideal lying over \mathfrak p \subset R. Then
H^ i(\omega _{A/R}^\bullet )_\mathfrak q \not= 0 \Rightarrow - d \leq i
where d is the dimension of the fibre of \mathop{\mathrm{Spec}}(A) \to \mathop{\mathrm{Spec}}(R) over \mathfrak p at the point \mathfrak q.
Proof.
Choose a factorization R \to P \to A with P = R[x_1, \ldots , x_ n] as in Section 47.24 so that \omega _{A/R}^\bullet = R\mathop{\mathrm{Hom}}\nolimits (A, P)[n]. We have to show that R\mathop{\mathrm{Hom}}\nolimits (A, P)_\mathfrak q has vanishing cohomology in degrees < n - d. By Lemma 47.13.3 this means we have to show that \mathop{\mathrm{Ext}}\nolimits _ P^ i(P/I, P)_{\mathfrak r} = 0 for i < n - d where \mathfrak r \subset P is the prime corresponding to \mathfrak q and I is the kernel of P \to A. We may rewrite this as \mathop{\mathrm{Ext}}\nolimits _{P_\mathfrak r}^ i(P_\mathfrak r/IP_\mathfrak r, P_\mathfrak r) by More on Algebra, Lemma 15.65.4. Thus we have to show
\text{depth}_{IP_\mathfrak r}(P_\mathfrak r) \geq n - d
by Lemma 47.11.1. By Lemma 47.11.5 we have
\text{depth}_{IP_\mathfrak r}(P_\mathfrak r) \geq \dim ((P \otimes _ R \kappa (\mathfrak p))_\mathfrak r) - \dim ((P/I \otimes _ R \kappa (\mathfrak p))_\mathfrak r)
The two expressions on the right hand side agree by Algebra, Lemma 10.116.4.
\square
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