Lemma 48.18.1. In Situation 48.16.1 let
be a cartesian diagram of \textit{FTS}_ S with g flat. Then there is an isomorphism L(g')^* \circ f^! \to (f')^! \circ Lg^* on D_\mathit{QCoh}^+(\mathcal{O}_ Y).
Lemma 48.18.1. In Situation 48.16.1 let
be a cartesian diagram of \textit{FTS}_ S with g flat. Then there is an isomorphism L(g')^* \circ f^! \to (f')^! \circ Lg^* on D_\mathit{QCoh}^+(\mathcal{O}_ Y).
Proof. Namely, because g is flat, for every choice of compactification j : X \to \overline{X} of X over Y the scheme \overline{X} is Tor independent of Y'. Denote j' : X' \to \overline{X}' the base change of j and \overline{g}' : \overline{X}' \to \overline{X} the projection. We define the base change map as the composition
where the middle arrow is the base change map (48.5.0.1) and a and a' are the right adjoints to pushforward of Lemma 48.3.1 for \overline{X} \to Y and \overline{X}' \to Y'. This construction is independent of the choice of compactification (we will formulate a precise lemma and prove it, if we ever need this result).
To finish the proof it suffices to show that the base change map L(g')^* \circ a \to a' \circ Lg^* is an isomorphism on D_\mathit{QCoh}^+(\mathcal{O}_ Y). By Lemma 48.4.4 formation of a and a' commutes with restriction to affine opens of Y and Y'. Thus by Remark 48.6.1 we may assume that Y and Y' are affine. Thus the result by Lemma 48.6.2. \square
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