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The Stacks project

Lemma 45.12.2. In the situation above. Let X \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{C}). Let \mathcal{E}_ i be a finite collection of locally free \mathcal{O}_ X-modules of rank r_ i. There exists a morphism p : P \to X in \mathcal{C} such that

  1. p^* : A(X) \to A(P) is injective,

  2. each p^*\mathcal{E}_ i has a filtration whose successive quotients \mathcal{L}_{i, 1}, \ldots , \mathcal{L}_{i, r_ i} are invertible \mathcal{O}_ P-modules.

Proof. We may assume r_ i \geq 1 for all i. We will prove the lemma by induction on \sum (r_ i - 1). If this integer is 0, then \mathcal{E}_ i is invertible for all i and we conclude by taking \pi = \text{id}_ X. If not, then we can pick an i such that r_ i > 1 and consider the projective bundle p : P \to X associated to \mathcal{E}_ i. We have a short exact sequence

0 \to \mathcal{F} \to p^*\mathcal{E}_ i \to \mathcal{O}_ P(1) \to 0

of finite locally free \mathcal{O}_ P-modules of ranks r_ i - 1, r_ i, and 1. Observe that p^* : A(X) \to A(P) is injective by assumption. By the induction hypothesis applied to the finite locally free \mathcal{O}_ P-modules \mathcal{F} and p^*\mathcal{E}_{i'} for i' \not= i, we find a morphism p' : P' \to P with properties stated as in the lemma. Then the composition p \circ p' : P' \to X does the job. \square


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