Proof.
We observe that property (3) is a consequence of properties (1) and (2). Namely, if s is a nonzero local section of F(G(\mathcal{N})) with \text{d}(s) = 0, then s cannot be in the image of \mathcal{N} \to F(G(\mathcal{N})). Hence we can write the image \overline{s} of s in the cokernel as \overline{\text{d}}(s') for some local section s' of \mathcal{N}. Then we see that s = \text{d}(s') because the difference s - \text{d}(s') is still in the kernel of \text{d} and is contained in the image of the counit.
Let us write temporarily \mathcal{A}_{gr}, respectively \mathcal{A}_{dg} the sheaf \mathcal{A} viewed as a (right) graded module over itself, respectively as a (right) differential graded module over itself. The most important case of the lemma is to understand what is G(\mathcal{A}_{gr}). Of course G(\mathcal{A}_{gr}) is the object of \textit{Mod}(\mathcal{A}, \text{d}) representing the functor
\mathcal{M} \longmapsto \mathop{\mathrm{Hom}}\nolimits _{\textit{Mod}(\mathcal{A})}(\mathcal{A}_{gr}, F(\mathcal{M})) = \Gamma (\mathcal{C}, \mathcal{M})
By Remark 24.22.5 we see that this functor represented by C[-1] where C is the cone on the identity of \mathcal{A}_{dg}. We have a short exact sequence
0 \to \mathcal{A}_{dg}[-1] \to C[-1] \to \mathcal{A}_{dg} \to 0
in \textit{Mod}(\mathcal{A}, \text{d}) which is split by the counit \mathcal{A}_{gr} \to F(C[-1]) in \textit{Mod}(\mathcal{A}). Thus G(\mathcal{A}_{gr}) satisfies properties (1) and (2).
Let U be an object of \mathcal{C}. Denote j_ U : \mathcal{C}/U \to \mathcal{C} the localization morphism. Denote \mathcal{A}_ U the restriction of \mathcal{A} to U. We will use the notation \mathcal{A}_{U, gr} to denote \mathcal{A}_ U viewed as a graded \mathcal{A}_ U-module. Denote F_ U : \textit{Mod}(\mathcal{A}_ U, \text{d}) \to \textit{Mod}(\mathcal{A}_ U) the forgetful functor and denote G_ U its adjoint. Then we have the commutative diagrams
\vcenter { \xymatrix{ \textit{Mod}(\mathcal{A}, \text{d}) \ar[d]_{j_ U^*} \ar[r]_ F & \textit{Mod}(\mathcal{A}) \ar[d]^{j_ U^*} \\ \textit{Mod}(\mathcal{A}_ U, \text{d}) \ar[r]^{F_ U} & \textit{Mod}(\mathcal{A}_ U) } } \quad \text{and}\quad \vcenter { \xymatrix{ \textit{Mod}(\mathcal{A}_ U, \text{d}) \ar[r]_{F_ U} \ar[d]_{j_{U!}} & \textit{Mod}(\mathcal{A}_ U) \ar[d]^{j_{U!}} \\ \textit{Mod}(\mathcal{A}, \text{d}) \ar[r]^ F & \textit{Mod}(\mathcal{A}) } }
by the construction of j^*_ U and j_{U!} in Sections 24.9, 24.18, 24.10, and 24.19. By uniqueness of adjoints we obtain j_{U!} \circ G_ U = G \circ j_{U!}. Since j_{U!} is an exact functor, we see that the properties (1) and (2) for the counit \mathcal{A}_{U, gr} \to F_ U(G_ U(\mathcal{A}_{U, gr})) which we've seen in the previous part of the proof imply properties (1) and (2) for the counit j_{U!}\mathcal{A}_{U, gr} \to F(G(j_{U!}\mathcal{A}_{U, gr})) = j_{U!}F_ U(G_ U(\mathcal{A}_{U, gr})).
In the proof of Lemma 24.11.1 we have seen that any object of \textit{Mod}(\mathcal{A}) is a quotient of a direct sum of copies of j_{U!}\mathcal{A}_{U, gr}. Since G is a left adjoint, we see that G commutes with direct sums. Thus properties (1) and (2) hold for direct sums of objects for which they hold. Thus we see that every object \mathcal{N} of \textit{Mod}(\mathcal{A}) fits into an exact sequence
\mathcal{N}_1 \to \mathcal{N}_0 \to \mathcal{N} \to 0
such that (1) and (2) hold for \mathcal{N}_1 and \mathcal{N}_0. We leave it to the reader to deduce (1) and (2) for \mathcal{N} using that G is right exact.
\square
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