Lemma 50.20.2. Let k be a field. Let X be a smooth proper scheme over k. The map
is zero.
Lemma 50.20.2. Let k be a field. Let X be a smooth proper scheme over k. The map
is zero.
Proof. Since X is smooth over k it is geometrically reduced over k, see Varieties, Lemma 33.25.4. Hence H^0(X, \mathcal{O}_ X) = \prod k_ i is a finite product of finite separable field extensions k_ i/k, see Varieties, Lemma 33.9.3. It follows that \Omega _{H^0(X, \mathcal{O}_ X)/k} = \prod \Omega _{k_ i/k} = 0 (see for example Algebra, Lemma 10.158.1). Since the map of the lemma factors as
by functoriality of the de Rham complex (see Section 50.2), we conclude. \square
Comments (0)
There are also: