Lemma 13.10.7. Let \mathcal{A} be an additive category. Let (A^\bullet , B^\bullet , C^\bullet , a, b, c) be a distinguished triangle in K(\mathcal{A}). Then there exists an isomorphic distinguished triangle (A^\bullet , (B')^\bullet , C^\bullet , a', b', c) such that 0 \to A^ n \to (B')^ n \to C^ n \to 0 is a split short exact sequence for all n.
Proof. We will use that K(\mathcal{A}) is a triangulated category by Proposition 13.10.3. Let W^\bullet be the cone on c : C^\bullet \to A^\bullet [1] with its maps i : A^\bullet [1] \to W^\bullet and p : W^\bullet \to C^\bullet [1]. Then (C^\bullet , A^\bullet [1], W^\bullet , c, i, -p) is a distinguished triangle by Lemma 13.9.14. Rotating backwards twice we see that (A^\bullet , W^\bullet [-1], C^\bullet , -i[-1], p[-1], c) is a distinguished triangle. By TR3 there is a morphism of distinguished triangles (\text{id}, \beta , \text{id}) : (A^\bullet , B^\bullet , C^\bullet , a, b, c) \to (A^\bullet , W^\bullet [-1], C^\bullet , -i[-1], p[-1], c) which must be an isomorphism by Lemma 13.4.3. This finishes the proof because 0 \to A^\bullet \to W^\bullet [-1] \to C^\bullet \to 0 is a termwise split short exact sequence of complexes by the very construction of cones in Section 13.9. \square
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