Lemma 88.19.6. The property $P(\varphi )=$“$\varphi $ is rig-étale” on arrows of $\textit{WAdm}^{Noeth}$ has the cancellation property as defined in Formal Spaces, Remark 87.21.18.
Proof. The statement makes sense by Lemma 88.19.1. To see that it is true assume we have maps $A \to B$ and $B \to C$ in $\textit{WAdm}^{Noeth}$ with $A \to C$ and $A \to B$ rig-étale. We have to show that $B \to C$ is rig-étale. Then we can choose an ideal of definition $I \subset A$ such that the topology on $C$ and $B$ is the $I$-adic topology. By Lemma 88.3.5 we obtain an exact sequence
There exists a $c \geq 0$ such that for all $a \in I$ multiplication by $a^ c$ is zero on $\mathop{N\! L}\nolimits _{B/A}^\wedge $ in $D(B)$ and $\mathop{N\! L}\nolimits _{C/A}^\wedge $ in $D(C)$. Hence $H^0(\mathop{N\! L}\nolimits _{B/A}^\wedge ) \otimes _ A C$, $H^0(\mathop{N\! L}\nolimits _{C/A}^\wedge )$, and $H^{-1}(\mathop{N\! L}\nolimits _{C/A}^\wedge )$ are annihilated by $a^ c$. From the exact sequence we obtain that multiplication by $a^{2c}$ is zero on $H^0(\mathop{N\! L}\nolimits _{C/B}^\wedge )$ and $H^{-1}(\mathop{N\! L}\nolimits _{C/B}^\wedge )$. It follows from Lemma 88.8.2 that $C$ is rig-étale over $(B, IB)$ as desired. $\square$
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