Lemma 59.94.2. In the situation above, if in addition f is quasi-compact and quasi-separated, then the diagram
is commutative.
Lemma 59.94.2. In the situation above, if in addition f is quasi-compact and quasi-separated, then the diagram
is commutative.
Proof. As in the proof of Lemma 59.94.1 we may replace S by \mathop{\mathrm{Spec}}(\mathcal{O}^{sh}_{S, \overline{s}}). Then our maps simplify to h : X_{\overline{t}} \to X, i : X_{\overline{s}} \to X, and \beta _{K, \overline{s}, \overline{t}} : K \to Rh_*(K|_{X_{\overline{t}}}). Using that (Rf_*K)_{\overline{s}} = R\Gamma (X, K) by Theorem 59.53.1 the composition of sp with the base change map (Rf_*K)_{\overline{t}} \to R\Gamma (X_{\overline{t}}, K) is just pullback of cohomology along h. This is the same as the map
Now the map cosp first inverts the = sign in this displayed formula, then pulls back along i, and finally applies the inverse of i^{-1}\beta _{K, \overline{s}, \overline{t}}. Hence we get the desired commutativity. \square
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