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The Stacks project

Lemma 87.36.2. Let S be a scheme. Suppose given a directed set \Lambda and a system of formal algebraic spaces (X_\lambda , f_{\lambda \mu }) over \Lambda where each f_{\lambda \mu } : X_\lambda \to X_\mu is a closed immersion inducing an isomorphism X_{\lambda , red} \to X_{\mu , red}. Then X = \mathop{\mathrm{colim}}\nolimits _{\lambda \in \Lambda } X_\lambda is a formal algebraic space over S.

Proof. Since we take the colimit in the category of fppf sheaves, we see that X is a sheaf. Choose and fix \lambda \in \Lambda . Choose a covering \{ X_{i, \lambda } \to X_\lambda \} as in Definition 87.11.1. In particular, we see that \{ X_{i, \lambda , red} \to X_{\lambda , red}\} is an étale covering by affine schemes. For each \mu \geq \lambda there exists a cartesian diagram

\xymatrix{ X_{i, \lambda } \ar[r] \ar[d] & X_{i, \mu } \ar[d] \\ X_\lambda \ar[r] & X_\mu }

with étale vertical arrows. Namely, the étale morphism X_{i, \lambda , red} \to X_{\lambda , red} = X_{\mu , red} corresponds to an étale morphism X_{i, \mu } \to X_\mu of formal algebraic spaces with X_{i, \mu } an affine formal algebraic space, see Lemma 87.34.4. The same lemma implies the base change of X_{i, \mu } to X_\lambda agrees with X_{i, \lambda }. It also follows that X_{i, \mu } = X_\mu \times _{X_{\mu '}} X_{i, \mu '} for \mu ' \geq \mu \geq \lambda . Set X_ i = \mathop{\mathrm{colim}}\nolimits X_{i, \mu }. Then X_{i, \mu } = X_ i \times _ X X_\mu (as functors). Since any morphism T \to X = \mathop{\mathrm{colim}}\nolimits X_\mu from an affine (or quasi-compact) scheme T maps into X_\mu for some \mu , we see conclude that \mathop{\mathrm{colim}}\nolimits X_{i, \mu } \to \mathop{\mathrm{colim}}\nolimits X_\mu is étale. Thus, if we can show that \mathop{\mathrm{colim}}\nolimits X_{i, \mu } is an affine formal algebraic space, then the lemma holds. Note that the morphisms X_{i, \mu } \to X_{i, \mu '} are closed immersions as a base change of the closed immersion X_\mu \to X_{\mu '}. Finally, the morphism X_{i, \mu , red} \to X_{i, \mu ', red} is an isomorphism as X_{\mu , red} \to X_{\mu ', red} is an isomorphism. Hence this reduces us to the case discussed in Lemma 87.36.1. \square


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