Lemma 87.37.1. Let S be a scheme. Let X be an affine formal algebraic space over S. Let T \subset |X_{red}| be a closed subset. Then the functor
is an affine formal algebraic space.
Lemma 87.37.1. Let S be a scheme. Let X be an affine formal algebraic space over S. Let T \subset |X_{red}| be a closed subset. Then the functor
is an affine formal algebraic space.
Proof. Write X = \mathop{\mathrm{colim}}\nolimits X_\lambda as in Definition 87.9.1. Then X_{\lambda , red} = X_{red} and we may and do view T as a closed subset of |X_\lambda | = |X_{\lambda , red}|. By Lemma 87.14.1 for each \lambda the completion (X_\lambda )_{/T} is an affine formal algebraic space. The transition morphisms (X_\lambda )_{/T} \to (X_\mu )_{/T} are closed immersions as base changes of the transition morphisms X_\lambda \to X_\mu , see Lemma 87.14.4. Also the morphisms ((X_\lambda )_{/T})_{red} \to ((X_\mu )_/T)_{red} are isomorphisms by Lemma 87.14.5. Since X_{/T} = \mathop{\mathrm{colim}}\nolimits (X_\lambda )_{/T} we conclude by Lemma 87.36.1. \square
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