Lemma 21.43.5. In the situation above, suppose that K is an object of \mathit{QC}(\mathcal{O}) and M arbitrary in D(\mathcal{O}). For every object U of \mathcal{C} we have
\mathop{\mathrm{Hom}}\nolimits _{D(\mathcal{O}_ U)}(K|_ U, M|_ U) = R\mathop{\mathrm{Hom}}\nolimits _{\mathcal{O}(U)}(R\Gamma (U, K), R\Gamma (U, M))
Proof. We may replace \mathcal{C} by \mathcal{C}/U. Thus we may assume U = X is a final object of \mathcal{C}. By Lemma 21.43.4 we see that K = Lf^*P where P = R\Gamma (U, K) = R\Gamma (X, K) = Rf_*K. Thus the result because Lf^* is the left adjoint to Rf_*(-) = R\Gamma (U, -). \square
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