The Stacks project

Lemma 50.18.2. Let $R_1 \to R_2$ be a ring homomorphism. For $i = 1, 2$ consider commutative diagrams

\[ \xymatrix{ 0 \ar[r] & K_ i^0 \ar[r] & L_ i^0 \ar[r] & M_ i^0 \ar[r] & 0 \\ & & L_ i^{-1} \ar[u]_{\partial _ i} \ar@{=}[r] & M_ i^{-1} \ar[u] } \]

of $R_ i$-modules as in Lemma 50.18.1. Assume we have maps $K_1^0 \to K_2^0$, $L_1^ j \to L_2^ j$, $M_1^ j \to M_2^ j$ compatible with the given ring map $R_1 \to R_2$ and compatible with the maps in the displayed diagrams. If the maps $M_1^ j \otimes _{R_1} R_2 \to M_2^ j$ are isomorphisms, then the diagrams

\[ \xymatrix{ \wedge ^ p(H^0(L_1^\bullet )) \ar[d] \ar[r]_-{c^ p} & \wedge ^ p(K_1^0) \otimes _{R_1} \det (M_1^\bullet ) \ar[d] \\ \wedge ^ p(H^0(L_2^\bullet )) \ar[r]^-{c^ p} & \wedge ^ p(K_2^0) \otimes _{R_2} \det (M_2^\bullet ) } \]

commute.

Proof. This follows from the explicit description of the map given in the proof of Lemma 50.18.1. Note that we need the assumption that $M_1^ j \otimes _{R_1} R_2 \to M_2^ j$ are isomorphisms to see that the basis we use for $M_1^{-1}$ maps to a basis for $M_2^{-1}$ (and hence in checking the compatibility in both constructions we can use the “same” basis). $\square$


Comments (0)

There are also:

  • 2 comment(s) on Section 50.18: Comparing sheaves of differential forms

Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 0H9F. Beware of the difference between the letter 'O' and the digit '0'.