Lemma 10.136.4. Let $R \to S$ be a ring map. Suppose we have $g_1, \ldots g_ m \in S$ which generate the unit ideal such that each $R \to S_{g_ i}$ is syntomic. Then $R \to S$ is syntomic.
Proof. This is true for being flat and for being of finite presentation by Lemmas 10.39.18 and 10.23.3. The property of having fibre rings which are local complete intersections is local on $S$ by its very definition, see Definition 10.135.1. $\square$
Post a comment
Your email address will not be published. Required fields are marked.
In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$
). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).
All contributions are licensed under the GNU Free Documentation License.
Comments (0)
There are also: