Lemma 29.4.1. Let i : Z \to X be a closed immersion of schemes. Let \mathcal{I} \subset \mathcal{O}_ X be the quasi-coherent sheaf of ideals cutting out Z. The functor
i_* : \mathit{QCoh}(\mathcal{O}_ Z) \longrightarrow \mathit{QCoh}(\mathcal{O}_ X)
is exact, fully faithful, with essential image those quasi-coherent \mathcal{O}_ X-modules \mathcal{G} such that \mathcal{I}\mathcal{G} = 0.
Proof.
A closed immersion is quasi-compact and separated, see Lemmas 29.2.6 and 29.2.7. Hence Schemes, Lemma 26.24.1 applies and the pushforward of a quasi-coherent sheaf on Z is indeed a quasi-coherent sheaf on X.
By Modules, Lemma 17.13.4 the functor i_* is fully faithful.
Now we turn to the description of the essential image of the functor i_*. We have \mathcal{I}(i_*\mathcal{F}) = 0 for any quasi-coherent \mathcal{O}_ Z-module, for example by Modules, Lemma 17.13.4. Next, suppose that \mathcal{G} is any quasi-coherent \mathcal{O}_ X-module such that \mathcal{I}\mathcal{G} = 0. It suffices to show that the canonical map
\mathcal{G} \longrightarrow i_* i^*\mathcal{G}
is an isomorphism1. In the case of schemes and quasi-coherent modules, working affine locally on X and using Lemma 29.2.1 and Schemes, Lemma 26.7.3 it suffices to prove the following algebraic statement: Given a ring R, an ideal I and an R-module N such that IN = 0 the canonical map
N \longrightarrow N \otimes _ R R/I,\quad n \longmapsto n \otimes 1
is an isomorphism of R-modules. Proof of this easy algebra fact is omitted.
\square
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Comment #3989 by Jonas Ehrhard on
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