Lemma 29.15.2. Let f : X \to S be a morphism of schemes. The following are equivalent
The morphism f is locally of finite type.
For all affine opens U \subset X, V \subset S with f(U) \subset V the ring map \mathcal{O}_ S(V) \to \mathcal{O}_ X(U) is of finite type.
There exist an open covering S = \bigcup _{j \in J} V_ j and open coverings f^{-1}(V_ j) = \bigcup _{i \in I_ j} U_ i such that each of the morphisms U_ i \to V_ j, j\in J, i\in I_ j is locally of finite type.
There exist an affine open covering S = \bigcup _{j \in J} V_ j and affine open coverings f^{-1}(V_ j) = \bigcup _{i \in I_ j} U_ i such that the ring map \mathcal{O}_ S(V_ j) \to \mathcal{O}_ X(U_ i) is of finite type, for all j\in J, i\in I_ j.
Moreover, if f is locally of finite type then for any open subschemes U \subset X, V \subset S with f(U) \subset V the restriction f|_ U : U \to V is locally of finite type.
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Comment #2783 by David Hansen on
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