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The Stacks project

Lemma 29.25.3. Let f : X \to S be a morphism of schemes. The following are equivalent

  1. The morphism f is flat.

  2. For every affine opens U \subset X, V \subset S with f(U) \subset V the ring map \mathcal{O}_ S(V) \to \mathcal{O}_ X(U) is flat.

  3. There exists an open covering S = \bigcup _{j \in J} V_ j and open coverings f^{-1}(V_ j) = \bigcup _{i \in I_ j} U_ i such that each of the morphisms U_ i \to V_ j, j\in J, i\in I_ j is flat.

  4. There exists an affine open covering S = \bigcup _{j \in J} V_ j and affine open coverings f^{-1}(V_ j) = \bigcup _{i \in I_ j} U_ i such that \mathcal{O}_ S(V_ j) \to \mathcal{O}_ X(U_ i) is flat, for all j\in J, i\in I_ j.

Moreover, if f is flat then for any open subschemes U \subset X, V \subset S with f(U) \subset V the restriction f|_ U : U \to V is flat.

Proof. This is a special case of Lemma 29.25.2 above. \square


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