Lemma 29.30.2. Let f : X \to S be a morphism of schemes. The following are equivalent
The morphism f is syntomic.
For every affine opens U \subset X, V \subset S with f(U) \subset V the ring map \mathcal{O}_ S(V) \to \mathcal{O}_ X(U) is syntomic.
There exists an open covering S = \bigcup _{j \in J} V_ j and open coverings f^{-1}(V_ j) = \bigcup _{i \in I_ j} U_ i such that each of the morphisms U_ i \to V_ j, j\in J, i\in I_ j is syntomic.
There exists an affine open covering S = \bigcup _{j \in J} V_ j and affine open coverings f^{-1}(V_ j) = \bigcup _{i \in I_ j} U_ i such that the ring map \mathcal{O}_ S(V_ j) \to \mathcal{O}_ X(U_ i) is syntomic, for all j\in J, i\in I_ j.
Moreover, if f is syntomic then for any open subschemes U \subset X, V \subset S with f(U) \subset V the restriction f|_ U : U \to V is syntomic.
Comments (2)
Comment #1868 by Kestutis Cesnavicius on
Comment #1903 by Johan on