Proof.
We have (1) implies (2) by Morphisms, Lemmas 29.44.11, 29.20.10, and 29.44.10. We have (2) implies (3) by Morphisms, Lemma 29.20.7. We have (3) implies (4) by the definition of proper morphisms and Morphisms, Lemmas 29.20.9 and 29.20.10.
Assume (4). Pick s \in S. By Morphisms, Lemma 29.20.7 we see that all the finitely many points of X_ s are isolated in X_ s. Choose an elementary étale neighbourhood (U, u) \to (S, s) and decomposition X_ U = V \amalg W as in Lemma 37.41.6. Note that W_ u = \emptyset because all points of X_ s are isolated. Since f is universally closed we see that the image of W in U is a closed set not containing u. After shrinking U we may assume that W = \emptyset . In other words we see that X_ U = V is finite over U. Since s \in S was arbitrary this means there exists a family \{ U_ i \to S\} of étale morphisms whose images cover S such that the base changes X_{U_ i} \to U_ i are finite. Note that \{ U_ i \to S\} is an étale covering, see Topologies, Definition 34.4.1. Hence it is an fpqc covering, see Topologies, Lemma 34.9.7. Hence we conclude f is finite by Descent, Lemma 35.23.23.
\square
Comments (2)
Comment #4586 by fherzig on
Comment #4766 by Johan on