Lemma 29.48.6. Let $f : Y \to X$ be a finite morphism with $X$ affine. There exists a diagram

\[ \xymatrix{ Z' \ar[rd] & Y' \ar[l]^ i \ar[d] \ar[r] & Y \ar[d] \\ & X' \ar[r] & X } \]

where

$Y' \to Y$ and $X' \to X$ are surjective finite locally free,

$Y' = X' \times _ X Y$,

$i : Y' \to Z'$ is a closed immersion,

$Z' \to X'$ is finite locally free, and

$Z' = \bigcup _{j = 1, \ldots , m} Z'_ j$ is a (set theoretic) finite union of closed subschemes, each of which maps isomorphically to $X'$.

**Proof.**
Write $X = \mathop{\mathrm{Spec}}(A)$ and $Y = \mathop{\mathrm{Spec}}(B)$. See also More on Algebra, Section 15.21. Let $x_1, \ldots , x_ n \in B$ be generators of $B$ over $A$. For each $i$ we can choose a monic polynomial $P_ i(T) \in A[T]$ such that $P(x_ i) = 0$ in $B$. By Algebra, Lemma 10.136.14 (applied $n$ times) there exists a finite locally free ring extension $A \subset A'$ such that each $P_ i$ splits completely:

\[ P_ i(T) = \prod \nolimits _{k = 1, \ldots , d_ i} (T - \alpha _{ik}) \]

for certain $\alpha _{ik} \in A'$. Set

\[ C = A'[T_1, \ldots , T_ n]/(P_1(T_1), \ldots , P_ n(T_ n)) \]

and $B' = A' \otimes _ A B$. The map $C \to B'$, $T_ i \mapsto 1 \otimes x_ i$ is an $A'$-algebra surjection. Setting $X' = \mathop{\mathrm{Spec}}(A')$, $Y' = \mathop{\mathrm{Spec}}(B')$ and $Z' = \mathop{\mathrm{Spec}}(C)$ we see that (1) – (4) hold. Part (5) holds because set theoretically $\mathop{\mathrm{Spec}}(C)$ is the union of the closed subschemes cut out by the ideals

\[ (T_1 - \alpha _{1k_1}, T_2 - \alpha _{2k_2}, \ldots , T_ n - \alpha _{nk_ n}) \]

for any $1 \leq k_ i \leq d_ i$.
$\square$

## Comments (0)