The image of a quasi-compact algebraic space under a surjective morphism is quasi-compact.
Lemma 67.8.6. Let S be a scheme.
If X \to Y is a surjective morphism of algebraic spaces over S, and X is quasi-compact then Y is quasi-compact.
If
\xymatrix{ X \ar[rr]_ f \ar[rd]_ p & & Y \ar[dl]^ q \\ & Z }
is a commutative diagram of morphisms of algebraic spaces over S and f is surjective and p is quasi-compact, then q is quasi-compact.
Proof.
Assume X is quasi-compact and X \to Y is surjective. By Definition 67.5.2 the map |X| \to |Y| is surjective, hence we see Y is quasi-compact by Properties of Spaces, Lemma 66.5.2 and the topological fact that the image of a quasi-compact space under a continuous map is quasi-compact, see Topology, Lemma 5.12.7. Let f, p, q be as in (2). Let T \to Z be a morphism whose source is a quasi-compact algebraic space. By assumption T \times _ Z X is quasi-compact. By Lemma 67.5.5 the morphism T \times _ Z X \to T \times _ Z Y is surjective. Hence by part (1) we see T \times _ Z Y is quasi-compact too. Thus q is quasi-compact.
\square
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