Lemma 83.5.11. In the situation of Definition 83.5.8. Let \phi : U \to X be a morphism of algebraic spaces over B. Assume
\phi is set-theoretically R-invariant,
R is reduced, and
X is locally separated over B.
Then \phi is R-invariant.
Lemma 83.5.11. In the situation of Definition 83.5.8. Let \phi : U \to X be a morphism of algebraic spaces over B. Assume
\phi is set-theoretically R-invariant,
R is reduced, and
X is locally separated over B.
Then \phi is R-invariant.
Proof. Consider the equalizer
algebraic space. Then Z \to R is an immersion by assumption (3). By assumption (1) |Z| \to |R| is surjective. This implies that Z \to R is a bijective closed immersion (use Schemes, Lemma 26.10.4) and by assumption (2) we conclude that Z = R. \square
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