Lemma 74.7.1. Let $S$ be a scheme. Let $\{ f_ i : T_ i \to T\} _{i \in I}$ be an fpqc covering of algebraic spaces over $S$. Suppose that for each $i$ we have an open subspace $W_ i \subset T_ i$ such that for all $i, j \in I$ we have $\text{pr}_0^{-1}(W_ i) = \text{pr}_1^{-1}(W_ j)$ as open subspaces of $T_ i \times _ T T_ j$. Then there exists a unique open subspace $W \subset T$ such that $W_ i = f_ i^{-1}(W)$ for each $i$.
Proof. By Topologies on Spaces, Lemma 73.9.5 we may assume each $T_ i$ is a scheme. Choose a scheme $U$ and a surjective étale morphism $U \to T$. Then $\{ T_ i \times _ T U \to U\} $ is an fpqc covering of $U$ and $T_ i \times _ T U$ is a scheme for each $i$. Hence we see that the collection of opens $W_ i \times _ T U$ comes from a unique open subscheme $W' \subset U$ by Descent, Lemma 35.13.6. As $U \to X$ is open we can define $W \subset X$ the Zariski open which is the image of $W'$, see Properties of Spaces, Section 66.4. We omit the verification that this works, i.e., that $W_ i$ is the inverse image of $W$ for each $i$. $\square$
Post a comment
Your email address will not be published. Required fields are marked.
In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$
). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).
All contributions are licensed under the GNU Free Documentation License.
Comments (0)
There are also: