Lemma 40.11.5. Notation and assumptions as in Situation 40.11.1. If the image a(R_1) is a locally closed subset of R_2 then it is a closed subset.
Proof. Let k \subset k' be a perfect closure of the field k. Let R_ i' be the restriction of R_ i via the morphism U' = \mathop{\mathrm{Spec}}(k') \to \mathop{\mathrm{Spec}}(k). Note that the morphisms R_ i' \to R_ i are universal homeomorphisms as compositions of base changes of the universal homeomorphism U' \to U (see diagram in statement of Lemma 40.10.4). Hence it suffices to prove that a'(R_1') is closed in R_2'. In other words, we may assume that k is perfect.
If k is perfect, then the closure of the image is a groupoid scheme Z \subset R_2, by Lemma 40.11.4. By the same lemma applied to \text{id}_{R_1} : R_1 \to R_1 we see that (R_2)_{red} is a groupoid scheme. Thus we may apply Lemma 40.11.2 to the morphism a|_{(R_2)_{red}} : (R_2)_{red} \to Z to conclude that Z equals the image of a. \square
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