Remark 100.4.6. The result of Lemma 100.4.5 can be generalized as follows. Let \mathcal{X} be an algebraic stack. Let U be an algebraic space and let f : U \to \mathcal{X} be a surjective morphism (which makes sense by Section 100.3). Let R = U \times _\mathcal {X} U, let (U, R, s, t, c) be the groupoid in algebraic spaces, and let f_{can} : [U/R] \to \mathcal{X} be the canonical morphism as constructed in Algebraic Stacks, Lemma 94.16.1. Then the image of |R| \to |U| \times |U| is an equivalence relation and |\mathcal{X}| = |U|/|R|. The proof of Lemma 100.4.5 works without change. (Of course in general [U/R] is not an algebraic stack, and in general f_{can} is not an isomorphism.)
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