Processing math: 100%

The Stacks project

Remark 100.4.6. The result of Lemma 100.4.5 can be generalized as follows. Let \mathcal{X} be an algebraic stack. Let U be an algebraic space and let f : U \to \mathcal{X} be a surjective morphism (which makes sense by Section 100.3). Let R = U \times _\mathcal {X} U, let (U, R, s, t, c) be the groupoid in algebraic spaces, and let f_{can} : [U/R] \to \mathcal{X} be the canonical morphism as constructed in Algebraic Stacks, Lemma 94.16.1. Then the image of |R| \to |U| \times |U| is an equivalence relation and |\mathcal{X}| = |U|/|R|. The proof of Lemma 100.4.5 works without change. (Of course in general [U/R] is not an algebraic stack, and in general f_{can} is not an isomorphism.)


Comments (0)

There are also:

  • 2 comment(s) on Section 100.4: Points of algebraic stacks

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.