Lemma 10.69.3. Let R \to R' be a flat ring map. Let M be an R-module. Suppose that f_1, \ldots , f_ r \in R form an M-quasi-regular sequence. Then the images of f_1, \ldots , f_ r in R' form a M \otimes _ R R'-quasi-regular sequence.
Proof. Set J = (f_1, \ldots , f_ r), J' = JR' and M' = M \otimes _ R R'. We have to show the canonical map \mu : R'/J'[X_1, \ldots X_ r] \otimes _{R'/J'} M'/J'M' \to \bigoplus (J')^ nM'/(J')^{n + 1}M' is an isomorphism. Because R \to R' is flat the sequences 0 \to J^ nM \to M and 0 \to J^{n + 1}M \to J^ nM \to J^ nM/J^{n + 1}M \to 0 remain exact on tensoring with R'. This first implies that J^ nM \otimes _ R R' = (J')^ nM' and then that (J')^ nM'/(J')^{n + 1}M' = J^ nM/J^{n + 1}M \otimes _ R R'. Thus \mu is the tensor product of (10.69.0.1), which is an isomorphism by assumption, with \text{id}_{R'} and we conclude. \square
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